Jaydee invested a total of 65000 in two accounts. The first account earned a rate of 3%(after a year). However, the second account suffered a 2% loss in the same time period. At the end of one year, the total amount of money gained was less than 2000. How much money was invested into each account?
V4x2 + x ? D. X B. V A 4x² + x C. 2 2. What is the radicand of the radical expression in problem number A 4x²+x B. 7 C. 2 D.X 3. If a > 0, then Va is the nath root of a D. index A. 72 B. positive c. negative
Step-by-step explanation:
The given quadrilateral ∆BCD consists of two triangles; ∆ABD and ∆BCD
The area of quadrilateral ABCD = The sum of the areas of ∆ABD and ∆BCD
The base length of the two triangles equals segment BD 11 cm
The height of triangle ∆ABD = 7 cm
The area of a triangle = (1/2) * Base length x Height
The area of triangle ∆ABD = (1/2) x 11 cm x 7 cm = 38.5 cm²
Similarly;
The area of triangle ∆BCD (1/2) x 11 cm x 5 cm = 27.5 cm²
The area of quadrilateral ABCD = 38.5 cm + 27.5 cm² = 66 cm²
The area of the given figure (quadrilateral ABCD) = 66 cm²
\huge\green{\overline{\quad\quad\quad\quad\quad\quad\quad\quad\quad \quad\quad\quad\quad\quad\quad\ \: }}The given quadrilateral ∆BCD consists of two triangles; ∆ABD and ∆BCD
The area of quadrilateral ABCD = The sum of the areas of ∆ABD and ∆BCD
The base length of the two triangles equals segment BD 11 cm
The height of triangle ∆ABD = 7 cm
The area of a triangle = (1/2) * Base length x Height
The area of triangle ∆ABD = (1/2) x 11 cm x 7 cm = 38.5 cm²
Similarly;
The area of triangle ∆BCD (1/2) x 11 cm x 5 cm = 27.5 cm²
The area of quadrilateral ABCD = 38.5 cm + 27.5 cm² = 66 cm²
The area of the given figure (quadrilateral ABCD) = 66 cm²
\huge\green{\overline{\quad\quad\quad\quad\quad\quad\quad\quad\quad \quad\quad\quad\quad\quad\quad\ \: }}
Comments
Post a Comment